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How does the intensity of a sound wave change if the distance from the
source is increased by a factor of 4?
A. The intensity decreases by a factor of 4.
B. The intensity increases to by a factor of 16.
c. The intensity decreases by a factor of 16.
D. The intensity increases by a factor of 4.

Respuesta :

Answer:

The new intensity decreases by a factor of 16.

Explanation:

The intensity of sound wave is given by :

[tex]I=\dfrac{P}{A}[/tex]

P is power

A is area

[tex]I=\dfrac{P}{4\pi r^2}[/tex]

or

[tex]I\propto \dfrac{1}{r^2}[/tex], r is distance from the source

If the distance from the  source is increased by a factor of 4, r' = 4r

So,

[tex]I'=\dfrac{1}{r'^2}\\\\I'=\dfrac{1}{(4r)^2}\\\\I'=\dfrac{1}{16}\times \dfrac{1}{r^2}\\\\I'=\dfrac{I}{16}[/tex]

So, the new intensity decreases by a factor of 16.

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