Answer:
The new intensity decreases by a factor of 16.
Explanation:
The intensity of sound wave is given by :
[tex]I=\dfrac{P}{A}[/tex]
P is power
A is area
[tex]I=\dfrac{P}{4\pi r^2}[/tex]
or
[tex]I\propto \dfrac{1}{r^2}[/tex], r is distance from the source
If the distance from the source is increased by a factor of 4, r' = 4r
So,
[tex]I'=\dfrac{1}{r'^2}\\\\I'=\dfrac{1}{(4r)^2}\\\\I'=\dfrac{1}{16}\times \dfrac{1}{r^2}\\\\I'=\dfrac{I}{16}[/tex]
So, the new intensity decreases by a factor of 16.