Answer:
0.45 miles
Explanation:
since, car will be running on the edge of track, distance covered in one lap by car will be equal to circumference of track.\
we will use value of pi as 22/7
Circumference for any circular shape is given by [tex]\piD[/tex][tex]\pi D[/tex]
Hence, in one lap [tex]\pi D[/tex] distance will be covered
in 7 laps [tex]7 \pi D[/tex] distance will be covered.
but is given that 7 laps should be equal to 10 miles
so 10 miles will be equal to [tex]7\pi D[/tex]
[tex]7\pi D= 10 \ miles\\=> 7*(22/7)* D= 10 \ miles\\=> 22D = 10 \ miles\\=> D = 10/22 \ miles\\=> D = 0.45 \ miles[/tex]
Thus, diameter of track will be 0.45 miles to meet the requirement.