Answer:
The Area is [tex]48ft^{2}[/tex]
Step-by-step explanation:
This problem bothers on the mensuration of solid ans flat shapes, cylinder and rectangle.
If you take a deeper look into this problem you will observe that the vertical cross section of the pool is a rectangular shape (flat).
in the rectangular shape, the length is the height of the pool
the width is the radius of the pool.
Given Data
Radius r = ?
C= 75.36 ft
Height h= 4 ft
we need to first solve for radius r,
we know that the circumference of a circle is expressed as
[tex]C= 2\pi r[/tex]
[tex]75.36= 2* 3.14*r\\75.36= 6.28r\\r= \frac{75.36}{6.28} \\r= 12 ft[/tex]
we can now solve for the area of the vertical cross section which is the area of the rectangle
[tex]Area= length * width\\Area= 4*12\\Area= 48 ft^{2}[/tex]
