Answer:
|x+12| = -(x+12); x>-11
Step-by-step explanation:
You have the following function
[tex]|x+12|\ if\ x>-11[/tex] (1)
you need to write the same expression but with no absolute value sign.
You use the following equivalence for a function with absolute value:
[tex]|x-a|=x-a\ \ \ if\ x>a\\\\|x-a|=-(x-a)\ \ \ if\ x<a\\\\|x-a|=0\ \ \ if\ x=a\\[/tex]
with a constant
In the case of the expression (1), you have:
[tex]|x+12|=|x-(-12)|\\\\x>-11\\\\[/tex]
So, x > a, and the solution is:
[tex]|x+12|=|x-(-12)|=-(x-(-12))=-(x+12)[/tex]
-(x+12)