Answer:
16.1 mm to the nearest tenth.
Step-by-step explanation:
The diagonal we are looking for will be the line that runs between two opposite corners of the rectangle, and through the center of the rectangle.
The dimensions of the rectangle are given as 8 mm by 14 mm by 6 mm ( Length, Breadth, Height)
We can form a right angled triangle between the diagonal, the length and the height, with the diagonal being the hypotenuse.
The next step is to use the Pythagoras' Theorem to solve for the hypotenuse side of the triangle.
This will be
diagonal =[tex]\sqrt{length^{2} + height^{2}}[/tex]
diagonal =[tex]\sqrt{8^{2} + 14^{2}}[/tex] = 16.12 mm [tex]\approx 16.1 mm[/tex]
