Answer:
Shown below.
Explanation:
In this case we need to compute a 90% confidence interval for the true difference between the mean elapsed time (sec) for fabric softener purchasers and washing-up liquid purchasers.
It is provided that these products were chosen because they are similar with respect to allocated shelf space and number of alternative brands.
The (1 - α)% confidence interval for the true difference between the means, when the population standard deviations are not known, is given as follows:
[tex]CI=(\bar x_{1}-\bar x_{2})\pm t_{\alpha/2, (n_{1}+n_{2}-2)}\times S_{p}\times\sqrt{\frac{1}{n_{1}}+\frac{1}{n_{2}}}[/tex]
Here,
[tex]\bar x_{1}=\text{sample mean for fabric softener purchasers}\\\bar x_{2}=\text{sample mean for washing-up liquid purchasers}\\S_{p}=\text{pooled standard deviation}[/tex]
The formula to compute the value of [pooled standard deviation is:
[tex]S_{p}=\sqrt{\frac{(n_{1}-1)s_{1}^{2}+(n_{2}-1)s_{2}^{2}}{n_{1}+n_{2}-2}}[/tex]