Question

Which function will have a y-intercept at –1 and an amplitude of 2?
f (x) = negative sine (X) minus 1
f (x) = negative 2 sine (x) minus 1
f (x) = negative cosine (x)
f (x) = negative 2 cosine (x) minus 1

Answer 1

Answer:

Options B and D.

Step-by-step explanation:

The general form of sine function

$h(x)=A\sin (Bx+C)+D$

where, |A| is amplitude, $\frac{2\pi}{B}$ is period, $\frac{-C}{B}$ is phase shift and D is y-intercept.

The general form of cosine function

$h(x)=A\cos (Bx+C)+D$

where, |A| is amplitude, $\frac{2\pi}{B}$ is period, $\frac{-C}{B}$ is phase shift and D is y-intercept.

In function, $f(x)=-\sin x-1$

Amplitude : $|A|=1$

y-intercept : -1

In function, $f(x)=-2\sin x-1$

Amplitude : $|A|=2$

y-intercept : -1

In function, $f(x)=-\cos x$

Amplitude : $|A|=1$

y-intercept : 0

In function, $f(x)=-2\cos x-1$

Amplitude : $|A|=2$

y-intercept : -1

Therefore, the correct options are B and D.

Answer 2

Answer:

B

Step-by-step explanation:

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