Answer:
[tex]\dfrac{40}{42}[/tex]
Step-by-step explanation:
Let the numerator of the fraction=x
Since the denominator of a fraction is two more than the numerator.
Denominator=x+2
The fraction is therefore:
[tex]\dfrac{x}{x+2}[/tex]
If both numerator and denominator are decreased by six, the fraction becomes:
[tex]\dfrac{x-6}{x+2-6}[/tex]
The simplified result is [tex]\dfrac{17}{18}[/tex]
Therefore:
[tex]\dfrac{x-6}{x+2-6}=\dfrac{17}{18}\\$Next, we solve for x\\Cross multiply\\18(x-6)=17(x+2-6)\\18(x-6)=17(x-4)\\Expand the bracket\\18x-108=17x-68\\Collect like terms\\18x-17x=-68+108\\x=40[/tex]
Substituting x=40 into the initial fraction
[tex]\dfrac{x}{x+2}=\dfrac{40}{40+2}=\dfrac{40}{42}[/tex]
Therefore, the original fraction is [tex]\dfrac{40}{42}[/tex]
