Answer:
5x (3-2x^2)
Step-by-step explanation:
so all you have to do is 15x-10x=5x right?, then all you have to do is 15/5=3. 10x/5x=2x. then subtract 1 from the exponents. then you get the answer. okay Im sure about the fist part and the divison but not the exponents, I did use a calculator to check it though.
The factorize equation is, [tex]\rm 5x (\sqrt{3} - \sqrt{2}x) (\sqrt{3}+\sqrt{2}x}) = 0[/tex].
The roots of the equation are [tex]0 , \ \dfrac{\sqrt{3}}{\sqrt{2} }, \dfrac{-\sqrt{3}}{\sqrt{2} }[/tex].
Given that,
Equation; [tex]\rm 15x - 10x^3[/tex]
We have to determine,
Factorize the equation and factor of the equation.
According to the question,
To factorize the equation and determine the factor of the equation following all the steps given below.
Equation; [tex]\rm 15x - 10x^3[/tex]
[tex]\rm = 15x - 10x^3 = 0 \\\\= 5x (3-2x^2) = 0[/tex]
[tex]\rm = 5x (3-2x^2) = 0\\\\ = 5x (\sqrt{3} - \sqrt{2x}) (\sqrt{3}+\sqrt{2x}) = 0[/tex]
[tex]\rm = 5x (\sqrt{3} - \sqrt{2}x) (\sqrt{3}+\sqrt{2}x}) = 0\\\\ The \ roots \ of \ the \ equation \ are;\\\\5x = 0, \ x = \dfrac{0}{5}, \ x =0\\\\\\[/tex]
[tex]\sqrt{3} - \sqrt{2x} = 0, \sqrt{2}x = \sqrt{3}, \ x = \dfrac{\sqrt{3} }{\sqrt{2} }\\\\ \sqrt{3} +\sqrt{2x} = 0, \sqrt{2}x = -\sqrt{3}, \ x =- \dfrac{\sqrt{3} }{\sqrt{2} }[/tex]
Hence, The roots of the equation are [tex]0 , \ \dfrac{\sqrt{3}}{\sqrt{2} }, \dfrac{-\sqrt{3}}{\sqrt{2} }[/tex].
For more details refer to the link given below.
https://brainly.com/question/11540485
