Question

The partial pressure of carbon dioxide in a mixture is 0.31 atm.

If the mole fraction of the carbon dioxide is 0.46, what is the

total pressure of the mixture?

Answer 1

Answer:

$P_{Co2}= X_{Co2} P_{tot}$

Where $P_{tot}$ represent the total pressure and $X_{Co2}$ the fraction of carbon dioxide is 0.46 and we can find the total pressure with this formula:

$P_{tot}= \frac{P_{Co2}}{X_{Co2}}$

And replacing we got:

$P_{tot}= \frac{0.31 atm}{0.46}= 0.674 atm$

Step-by-step explanation:

For this case the partial presure of carbon dioxide is given by:

$P_{Co2}= X_{Co2} P_{tot}$

Where $P_{tot}$ represent the total pressure and $x_{Co2}$ the fraction of carbon dioxide is 0.46 and we can find the total pressure with this formula:

$P_{tot}= \frac{P_{Co2}}{X_{Co2}}$

And replacing we got:

$P_{tot}= \frac{0.31 atm}{0.46}= 0.674 atm$