Question

Leanne is trying to convert x^2+4x-6=0 the standard form to vertex form by completing the square which equation shows the correct form

Answer 1

Answer:

In vertex form we have y =      (x + 2)^2 - 10

Step-by-step explanation:

x^2+4x-6=0 is in standard form; we want it in the form y - k = a(x - h)^2.

Complete the square within  x^2+4x-6=0

We get  x^2 + 4x - 6 = 0  =>  x^2 + 4x + 4 - 4 - 6, or

                                          y =      (x + 2)^2 - 10

Comparing this to              y = (x - h)^2 - 10, we see that the vertex is at

                                            (h, k) :  (-2, -10)

Answer 2

Answer: $(x+2)^2-10=0$

Step-by-step explanation:

$x^2+4x-6=0$

Let 0 = y to not mix up the numbers.

$x^2+4x-6=y$

we are trying to get to this form: $y=a(x-h)^2+k$

Let's group the variables to make it easier for us to complete the square.

$(x^2+4x)-6=y$

Complete the square by taking the number next to the x variable (4) divide it by 2 (4/2=2) and square it ($2^2=4$)

Add this.

$(x^2+4x+4)-6=y$

You also have to add it to the right side, but since we're looking to isolate y again, we're going to have to move it to the left side eventually; therefore, we can simply change the sign and add it to the left side.

In other words, instead of doing this:

$-6=y+4\\-6-4=y$

I'm going to directly say the opposite of +4 is -4

$(x^2+4x+4)-6-4=y$

Now factor the parentheses and combine like terms;

$(x+2)^2-10=y$

And like we said y = 0, so change that...

$(x+2)^2-10=0$