Respuesta :
Answer:
0.5584 probability that she succeeds at 10 or more free-throws in a sample of 12 free-throws.
Step-by-step explanation:
For each free throw, there are only two possible outcomes. Either she makes it, or she does not. The probability of making a free throw is independent of other free throws. So we use the binomial probability distribution to solve this question.
Binomial probability distribution
The binomial probability is the probability of exactly x successes on n repeated trials, and X can only have two outcomes.
[tex]P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}[/tex]
In which [tex]C_{n,x}[/tex] is the number of different combinations of x objects from a set of n elements, given by the following formula.
[tex]C_{n,x} = \frac{n!}{x!(n-x)!}[/tex]
And p is the probability of X happening.
The probability that Shruti succeeds at any given free-throw is 80%, percent.
This means that [tex]p = 0.8[/tex]
Sample of 12 free throws:
This means that [tex]n = 12[/tex]
Use her results to estimate the probability that she succeeds at 10 or more free-throws in a sample of 12 free-throws.
[tex]P(X \geq 10) = P(X = 10) + P(X = 11) + P(X = 12)[/tex]
In which
[tex]P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}[/tex]
[tex]P(X = 10) = C_{12,10}.(0.8)^{10}.(0.2)^{2} = 0.2835[/tex]
[tex]P(X = 11) = C_{12,11}.(0.8)^{11}.(0.2)^{1} = 0.2062[/tex]
[tex]P(X = 12) = C_{12,12}.(0.8)^{12}.(0.2)^{0} = 0.0687[/tex]
[tex]P(X \geq 10) = P(X = 10) + P(X = 11) + P(X = 12) = 0.2835 + 0.2062 + 0.0687 = 0.5584[/tex]
0.5584 probability that she succeeds at 10 or more free-throws in a sample of 12 free-throws.
Answer:0.8
Step-by-step explanation:in 5 of the 25 stimulated trials, scrutiny continued federal than 10 successes
