janinnestrickland200
janinnestrickland200 janinnestrickland200
  • 29-05-2020
  • Mathematics
contestada

probability
0
1/2
1/5
1??​

probability012151 class=

Respuesta :

xplicifire
xplicifire xplicifire
  • 29-05-2020

Answer:

1

Step-by-step explanation:

Total number of portions = 10

unshaded portion= 5

number of even numbers =

probability of unshaded portion = 5/10 = 1/2

probability of even number = 5/10 = 1/2

Probability of landing on unshaded or even portion= probability of landing on unshaded portion + probability of landing on even number = 1/2 + 1/2 = 1

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