Question

What is the length c of the right triangle, rounded to the nearest
tenth?

Answer 1

Answer:

6.1

Step-by-step explanation:

we will name the length in front of the angle , y :

tan(71°)≅2.904= y ÷2

⇒ y=  5.8

and we know that

c = $\sqrt{2^{2} + y^{2} }$

then  

c = 6.14

and if we round it to the nearest tenth :

c = 6.1