Answer:
r = 1
Step-by-step explanation:
Given
[tex]\frac{4r-3}{6r+1}[/tex] = [tex]\frac{2r-1}{3r+4}[/tex] ( cross- multiply )
(6r + 1)(2r - 1) = (3r + 4)(4r - 3)
Expand factors on both sides using FOIL
12r² - 4r - 1 = 12r² + 7r - 12 ( subtract 12r² from both sides )
- 4r - 1 = 7r - 12 ( subtract 7r from both sides )
- 11r - 1 = - 12 ( add 1 to both sides )
- 11r = - 11 ( divide both sides by - 11 )
r = 1
