Answer:
[tex]\frac{1}{6} ,\frac{1}{6} ,\frac{1}{36}\,,\,independent[/tex]
Step-by-step explanation:
Given: Let A be the event that the first die lands on 2 and B be the event that the second die lands on 2.
To find:
P(A), the probability that the first die lands on 2
P(B), the probability that the second die lands on 2
P(A and B): the probability that the first die lands on 2 and the second die lands on 2
Solution:
Probability refers to chances of occurrence of some event.
Probability = number of favourable outcomes/total number of outcomes
Sample space = [tex]\left \{ 1,2,3,4,5,6 \right \}[/tex]
Total number of outcomes = 6
For P(A):
Number of favourable outcomes = 1
So,
[tex]P(A)=\frac{1}{6}[/tex]
For P(B):
Number of favourable outcomes = 1
So,
[tex]P(B)=\frac{1}{6}[/tex]
P(A and B) = [tex]P(A)P(B)=\left ( \frac{1}{6} \right )\left ( \frac{1}{6} \right )=\frac{1}{36}[/tex]
Yes, A and B are independent events as happening of each of the event does not depend on the other.