Question

Balance the equation NH3+O2--->N2+H2O given 1.37 mol of the reactant NH3 , determine the corresponding amount of O2. Answer in units of mol.?
Find the corresponding amount of N2. Answer in units of mol.

Find the corresponding amount of H2O. Answer in units of mol.

Given 3.82 mol of the product N2, find the corresponding amount of NH3. Answer in units of mol.

Find the corresponding amount of O2. Answer in units of mol.

Find the corresponding amount of N2. Answer in units of mol.

Find the corresponding amount of H2O. Answer in units of mol.

Answer 1

Answer:

O2 $= 1.822$ moles

N2 $= 0.685$ moles

H2O $= 2.055$ moles

Explanation:

The balanced oxidation reaction of ammonia is

4NH3 + 3O2 → 2N2 + 6H2O

Here 4 moles of ammonia (NH3) combine with 3 molecule of oxygen gas i.e O2.

1 mole of NH3 will combine with $\frac{4}{3} = 1.333$ moles of Oxygems

Now, $1.37$ moles of NH3 shall combine with $1.37 * 1.33 = 1.822$ moles of oxygen (O2)

4 mole of NH3 produces 2 moles of N2.

1 mole of NH3 will produce 0.5 moles of N2

1.37 moles of NH3 will produce 0.685 moles of N2

Like wise,

1.37 moles of NH3 will produce $\frac{6* 1.37}{4} = 2.055$ moles of water

Answer 2

O₂ moles = 1.822 moles

N₂ moles = 0.685 moles

H₂O moles = 2.055 moles

Number of moles:

A mole is defined as the mass of the substance which consists of the equal quantity of basic units.

• The balanced oxidation reaction of ammonia is

4NH₃ + 3O₂ → 2N₂ + 6H₂O

Here 4 moles of ammonia (NH₃) combine with 3 molecule of oxygen gas i.e. O₂ to produce 2 moles of nitrogen and 6 moles of water.

• 1 mole of NH₃ will combine with $\frac{4}{3}=1.33$ moles of Oxygen.

Now, 1.37 moles of NH₃ shall combine with $1.37*1.33=1.822$ moles of oxygen (O₂)

4 mole of NH₃ produces 2 moles of N₂.

• 1 mole of NH₃ will produce 0.5 moles of N₂.

1.37 moles of NH₃ will produce 0.685 moles of N₂.

• 1.37 moles of NH₃ will produce $\frac{6*1.37}{4} =2.055$  moles of water.

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