Question

Consider a system of four gases. The equilibrium concentration of each product is 2.3 M and the equilibrium concentrations of the reactants are equal. The equilibrium is shown here:

A + B C + D K = 2.6

What is the equilibrium concentration of gas A?

Answer 1

Answer:

The equilibrium concentration of gas A is 1.43 M

Explanation:

Here we have the reaction expressed as follows;

A + B → C + D and

The formula for equilibrium constant is therefore presented as follows;

$K = \frac{[C]\times [D]}{[A]\times [B]}$

Where:

[C] = [D] = 2.3 M

[A] = [B]

K = 2.6

Hence, we have;

$2.6 = \frac{2.3\times 2.3}{[A]\times [A]} = \frac{5.29}{[A]^2}$

$[A]^2= \frac{5.29}{2.6} = 2.03$

[A] = 1.43 M

The equilibrium concentration of gas A = 1.43 M.

Answer 2

Answer:

The equilibrium concentration of gas A = 1.43 M

Explanation:

First set up the equilibrium expression:

$K = \frac{[C]\times [D]}{[A]\times [B]}$

The problem states that each product has a concentration of 2.3M at equilibrium, and that k=2.6

We also know that [A] and [B] are the same.

Since we are solving for [A] I'm going to change [A][B] to A²

$2.6 =\frac{2.3^2}{A^2}$

Now we just need to solve for A²

A² = 5.29 / 2.6

A² = 2.0346

A = √2.0346

A = 1.43

Therefore, the equilibrium concentration of gas A = 1.43 M.