Corrected Question
Determine the values of a, b and c that make each equation true.
[tex](x^a)^6=\dfrac{1}{x^{30}} \\\\(x^{-7})^{-4}=x^b\\\\(x^{-2})^c=x^{22}[/tex]
Answer:
Step-by-step explanation:
To solve for a,b and c, we apply the following laws of indices
[tex]\dfrac{1}{p^m}=p^{-m} \\\\(a^m)^n=a^{m X n}\\\\$If p^m=p^n,$ then m=n[/tex]
Therefore :
Part 1
[tex](x^a)^6=\dfrac{1}{x^{30}}\\\\x^{a*6}=x^{-30}\\6a=-30\\$Divide both sides by 6\\a=-5[/tex]
Part 2
To solve for b
[tex](x^{-7})^{-4}=x^b\\x^{-7*-4}=x^b\\x^{28}=x^b\\$Since they have the same base\\b=28[/tex]
Part 3
To solve for c
[tex](x^{-2})^c=x^{22}\\x^{-2*c}=x^{22}\\$Just as in part 2, the two sides of the equality have the same base, therefore:\\-2c=22\\Divide both sides by -2\\c=-11[/tex]