Answer:
On the circle
Step-by-step explanation:
The distance between D and G is:
[tex]\sqrt{(-1-(-10))^2+(3-1)^2}=\sqrt{9^2+2^2}=\sqrt{81+5}=\sqrt{86}[/tex]
If point J is not exactly this far, then it is not on the circle.
[tex]\sqrt{(-1-(-3))^2+(12-3)^2}=\sqrt{2^2+9^2}=\sqrt{5+81}=\sqrt{86}[/tex]
Therefore, it is on the circle. Hope this helps!
