Please help and show work and steps

Answer:
I and III
Step-by-step explanation:
On a unit circle, the only two angles whose sine is [tex]-\dfrac{\sqrt{3}}{2}[/tex] are [tex]\dfrac{4\pi}{3}[/tex] and [tex]\dfrac{5\pi}{3}[/tex], otherwise known as [tex]-\dfrac{\pi}{3}[/tex]. Therefore, the correct answers are I and III. You can see the unit circle below, where the y coordinates of the above angles show [tex]-\dfrac{\sqrt{3}}{2}[/tex].