Answer:
Perimeter of the quadrilateral PQRS is 25 units
Step-by-step explanation:
From the figure attached,
PQ is a tangent to the given circle so m∠PQR = 90°
Now we apply Pythagoras theorem in the ΔPQR,
PR² = PQ² + QR²
(PT + TR)²= PQ² + 5²
(4 + 5)² = PQ² + 25
81 = PQ² + 25
PQ = √(81 - 25)
= √56
≈ 7.5 units
PQ ≅ PS ≅ 7.5 units
[Since measures of tangents drawn from a point to a circle are always equal]
Perimeter of PQRS = PQ + QR + RS + PS
= 7.5 + 5 + 5 + 7.5
= 25 units
Therefore, perimeter of the quadrilateral PQRS is 25 units.
Answer:
10 + 4 square root 14
Step-by-step explanation:
so the person below or above me said 25 units and they are not wrong it just the did have it in a simple equation like this ^
so 4 square root 14 = 14.9 or 15
then 10 + 15 = 25 units
so the correct answer is 10 + 4 square root 14
I ALSO TOOK THE TEST AND IT WAS CORRECT :)
