Answer:
About [tex]905in^{3} of air[/tex]
Step-by-step explanation:
This problem bothers on the mensuration of solid shapes. a sphere
yes an inflate ball takes the shape of a sphere.
Given data
Volume v = ?
Diameter d= [tex]12 in[/tex]
Radius r = [tex]\frac{diameter}{2} = \frac{12}{2} = 6in[/tex]
The expression for the volume of a sphere is
[tex]volume= \frac{4}{3}\pi r^{3} \\volume= \frac{4}{3} *3.142*6^{3} \\volume= \frac{12.57}{3} *216\\volume= \frac{2715.12}{3}\\ volume = 905.04 in^{3}[/tex]
Approximately the ball hold about [tex]905in^{3} of air[/tex]
