Question

Finding the Surface Area of a Rectangular Pyrammu

Try it

Henrique drew and labeled the net shown. He also

labeled the areas of the left and right triangular sides.

Use Henrique's work and finish finding the areas of the

faces.

What is the surface area of the rectangular pyramid?

13.6 in.)

13.6 in

4 in

10 in.

Answer 1

Answer:

The total surface area is 117.2 square inches.

Step-by-step explanation:

The surface area of a rectangular pyramid is formed by one rectangle at the center, and four triangles attached to it.

In this case, the rectangle has dimensions of 10 inches (height) by 4 inches (length). 2 triangles have a base of 10 inches and a height of 5 inches. The other 2 triangles have a an area of 13.6 square inches.

Basically, we need to find the area of the other two triangles and the area of the rectangle at the center.

Area of the rectangle.

$A_{1}=4 \times 10 = 40 \ in^{2}$

Area of the missing triangles.

$A_{2}= 2(\frac{1}{2} \times 10 \times 5 )=2(25) \ in^{2} = 50 \ in^{2}$

Now, we sum all areas

$A=40 + 50 + 13.6 +13.6= 117.2 \ in^{2}$

Therefore, the total surface area is 117.2 square inches.

Answer 2

Answer:

The answer is 117.2 square in

Step-by-step explanation:

I did it on edge and also the person above is correct have a wonderful day

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