A superhero is trying to leap over a tall building. The function f(x)=-16x^2+200x gives the superhero's height in feet as a function of time. The building is 612 feet high. Will the superhero make it over the building

Respuesta :

Answer:

Since [tex]\bigtriangleup \geq 0[/tex], the superhero makes it over the building.

Step-by-step explanation:

The height is given by the following function:

[tex]f(x) = -16x^{2} + 200x[/tex]

Will the superhero make it over the building?

We have to find if there is values of x for which f(x) = 612.

Solving a quadratic equation:

Given a second order polynomial expressed by the following equation:

[tex]ax^{2} + bx + c, a\neq0[/tex].

This polynomial has roots [tex]x_{1}, x_{2}[/tex] such that [tex]ax^{2} + bx + c = a(x - x_{1})*(x - x_{2})[/tex], given by the following formulas:

[tex]x_{1} = \frac{-b + \sqrt{\bigtriangleup}}{2*a}[/tex]

[tex]x_{2} = \frac{-b - \sqrt{\bigtriangleup}}{2*a}[/tex]

[tex]\bigtriangleup = b^{2} - 4ac[/tex]

If [tex]\bigtriangleup < 0[/tex], the polynomial has no solutions.

In this question:

[tex]f(x) = -16x^{2} + 200x[/tex]

[tex]-16x^{2} + 200x = 612[/tex]

[tex]16x^{2} - 200x + 612 = 0[/tex]

We have to find [tex]\bigtriangleup[/tex]

We have that [tex]a = 16, b = -200, c = 612[/tex]. So

[tex]\bigtriangleup = (-200)^{2} - 4*16*612 = 832[/tex]

Since [tex]\bigtriangleup \geq 0[/tex], the superhero makes it over the building.

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