Answer:
[tex]\frac{a+5}{a-1}[/tex]
Step-by-step explanation:
Given
f(x) = [tex]\frac{3+x}{x-3}[/tex]
To evaluate f(a + 2) substitute x = a + 2 into f(x), that is
f(a + 2) = [tex]\frac{3+a+2}{a+2-3}[/tex] = [tex]\frac{a+5}{a-1}[/tex]
