Question

Which equations represent the line that is parallel to 3x − 4y = 7 and passes through the point (−4, −2)? Select two options.

y = –Three-fourthsx + 1
3x − 4y = −4
4x − 3y = −3
y – 2 = –Three-fourths(x – 4)
y + 2 = Three-fourths(x + 4)

Answer 1

Answer:

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3x - 4y = 7

-4y = -3x + 7

y = 3/4x - 7/4.....the slope here is 3/4. A parallel line will have the same slope.

y - y1 = m(x - x1)

slope(m) = 3/4

(-4,-2)....x1 = -4 and y1 = -2

now we sub

y - (-2) = 3/4(x - (-4) =

y + 2 = 3/4(x + 4) <=== this is one

y + 2 = 3/4(x + 4)

y + 2 = 3/4x + 3

y = 3/4x + 3 - 2

y = 3/4x + 1

-3/4x + y = 1

3x - 4y = -4 <==== this is one

Answer 2

The equation of the line is y + 2 = 3/4(x + 4)

How to determine the equation?

We have:

3x- 4y = 7

Make y the subject

-4y = -3x + 7

Divide through by -4

y = 3/4 x - 7/4

A linear equation is represented as:

y = mx + c

Where m represents the siope.

This means that:

m = 3/4

Parallel lines have the same slope.

So, the equation of the new line is:

y - y1 = m(x - x1)

Where:

(x1, y1) = (-4, -2)

This gives

y + 2 = 3/4(x + 4)

Hence, the equation of the line is y + 2 = 3/4(x + 4)

Read more about linear equations at:https://brainly.com/question/14323743

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