Question

Factor 2m^3-12m^2+18m completely

A. 2m(m-3)^2
B. 2m(m^2-6m+9)
C. 2m(m-3)(m+3)
D. 2(m^3-6m^2+9m)

Answer 1

Answer:

The answer is A.

Step-by-step explanation:

Firstly, you have to take out the common terms for this expression. In this expression, the common terms ard 2 and m :

$2 {m}^{3} - 12 {m}^{2} + 18m$

$= 2( {m}^{3} - 6 {m}^{2} + 9m)$

$= 2m( {m}^{2} - 6m + 9)$

Next you have to factorise the brackets :

${m}^{2} - 6m + 9$

$= {m}^{2} - 3m - 3m + 9$

$= m(m - 3) - 3(m - 3)$

$= (m - 3)(m - 3)$

$= {(m - 3)}^{2}$

So the final answer is :

$2m {(m - 2)}^{2}$

Answer 2

Answer:

ANSWER A is correct.

your answer is attached to the picture.

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