Answer:
1. [tex]14\geq 3x[/tex]
The maximum number of rides he could go on is 4.
2. [tex]39\geq 11x[/tex]
Step-by-step explanation:
He has a total of $19 to spend. Therefore we can say that whatever we are going to spend has to be less than or equal to $19.
[tex]19\geq x[/tex]
She paid $5 for admission
[tex]19\geq 5[/tex]
Rides cost $3 each. (Let x be the number of rides)
3x (three dollars for every ride x)
Add this to the original inequality.
[tex]19\geq 5+3x[/tex]
Since we are asked to find the number of rides she can ride, solve for x:
Start by subtracting 5.
[tex]19-5\geq 3x[/tex]
Combine like terms;
[tex]14\geq 3x[/tex]
Divide by 3.
[tex]\frac{14}{3}\geq x[/tex]
Divide.
14/3=4.6
12
------
20
18
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20
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We conclude that the maximum number of rides he could go on is 4
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Amanda has $40 to spend. Again, this means she can spend a maximum of 40. So, anything (x) has to be less than or equal to 40 ([tex]40\geq x[/tex])
She wants to buy a pair of flowers for $1
[tex]40\geq 1[/tex]
The rest of the money will be spent on lily flowers. Each lily flower costs $11. Again, multiply 11 by the number of lily flowers, which we don't know so we'll call it x (11x)
Add it to the inequality
[tex]40\geq 1+11x[/tex]
Solve for x; begin by subtracting 1
[tex]40-1\geq 11x[/tex]
Combine like terms;
[tex]39\geq 11x[/tex]
Divide by 11
[tex]\frac{39}{11}\geq x[/tex]
