Question

8)
75.0 g of glucose (molar mass = 180 g/mol) is dissolved in 250 mL of solution. What is the molarity of this solution?

Answer 1

Answer:

1.67 M

Explanation:

75.0 g *1 mol/180 g = (75/180) mol of glucose

250 mL = 0.250 L

(75/180)/0.250 = 1.67 mol/L =1.67 M

Answer 2

The molarity of the solution is the property used to calculate the moles, volume, and concentration. The molarity of 75 gm glucose solution is 1.67 M.

What is molarity?

Molarity is the division of moles and volume. The volume of the solution for calculating concentration must be in liters.

Given,

Mass (glucose) = 75 gms

Molar mass (glucose) = 180 g/mol

Volume (V) = 250 mL

As it is known,

Moles (n) = Mass ÷ Molar mass

Molarity (M) = moles ÷ volume

M = mass ÷ (molar mass × volume)

M = 75 ÷ (180 × 0.25)

= 1.666 M

Therefore, 1.67 M is the molarity of the glucose solution.

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