Let 0 = [tex]a_{n}[/tex], 84 = a, 74 = [tex]a_{2}[/tex], and d, which is the difference between consecutive terms, be 74 - 84 = -10.
[tex]a_{n}[/tex] = a + (n-1)d
0 = 84 + (n-1)-10
0 = 84 - 10n + 10
0 = 94 - 10n
10n = 94
n = 9.4
The equation gives us the answer that 0 is the 9.4th term of the equation. But since n is always a natural number for a number in the series, we can say that 0 is not a part of this series.
