The two values of x that are roots of the equation are;
x = -(3+√29)/2, -(3-√29)/2. In decimal form; x = 1.19, -4.19.
What are the roots of the equation?
Given the equation; x² + 3x - 5 = 0
We use the quadratic formula to solve for the roots.
[-b±√( b² - 4(ac) )] / 2a
From the equation;
We substitute our values into the equation above
{[-b±√( b² - 4(ac) )] / 2a} = 0
{[-3±√( 3² - 4(1 × -5) )] / 2×1} = 0
[-3±√29 ] / 2 = 0
Hence
x = [-3 - √29 ] / 2 or [-3 + √29 ] / 2
The two values of x that are roots of the equation are;
x = -(3+√29)/2, -(3-√29)/2 or In decimal form; x = 1.19, -4.19.
Learn more about quadratic formula here: brainly.com/question/1863222
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