Question

You roll a six-sided die.
Event A: Roll an odd number.
Event B: Roll a number less than 5.
Find P(A or B). Express you answer as a fraction in simplest form.

Answer 1

Answer:

Judging by the question, this isn't a hard problem. all you have to do is roll a die 2x's. write down the first and second number into a fraction and then simplify it. for example, say if a roll a 2 and then a 5. my answer would be 2/5 and in this case i would not have to simplify it. hope this helps

Answer 2

P(A or B) = $\frac{1}{6}$

Formula: P(AUB)=P(A)+P(B)-P(A n B)

We roll six-sided die.

Then sample space ={1,2,3,4,5,6}

And

Event A: Roll an odd number.

Odd numbers are {1,3,5}

Event B: Roll a number less than 5

Number less than 5 are {1,2,3,4}

So, Probability P(A)= $\frac{3}{6}$

Probability P(B)= $\frac{4}{6}$

Now, the odd number which is less than 5 are {1,3}

So, P(A n B)=$\frac{2}{6}$

Since P(AUB)=P(A)+P(B)-P(A n B)

$P(AUB)=\frac{3}{6}+ \frac{4}{6}-\frac{2}{6}\\P(AUB)=\frac{5}{6}$

Therefore, P(A or B) = $\frac{1}{6}$

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