Respuesta :

Answer:

The positions can be filled in 150 ways.

Step-by-step explanation:

The order in which the people are chosen is not important. For example, A, B, C, D is the same outcome as B, A, C, D. So we use the combinations formula to solve this question.

Combinations formula:

[tex]C_{n,x}[/tex] is the number of different combinations of x objects from a set of n elements, given by the following formula.

[tex]C_{n,x} = \frac{n!}{x!(n-x)!}[/tex]

In how many ways can the positions be filled if 2 women and 2 men are hired?

2 women from a set of 6.

2 men from a set of 5.

So

[tex]T = C_{6,2} \times C_{5,2} = \frac{6!}{2!(6-2)!} \times \frac{5!}{2!(5-2)!} = 120[/tex]

The positions can be filled in 150 ways.

The number of ways the position can be filled with 2 women and 2 mean is 150

The number of people is:

[tex]\mathbf{Women = 6}[/tex]

[tex]\mathbf{Men = 5}[/tex]

The number of selection is:

[tex]\mathbf{Women = 2}[/tex]

[tex]\mathbf{Men = 2}[/tex]

So, the number of ways of selection is calculated using:

[tex]\mathbf{Ways = ^nC_r}[/tex]

This gives

[tex]\mathbf{Ways = ^6C_2 \times ^5C_2}[/tex]

Apply combination formula

[tex]\mathbf{Ways =15 \times 10}[/tex]

[tex]\mathbf{Ways =150}[/tex]

Hence, the number of ways the position can be filled with 2 women and 2 mean is 150

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