Respuesta :
Answer:
The positions can be filled in 150 ways.
Step-by-step explanation:
The order in which the people are chosen is not important. For example, A, B, C, D is the same outcome as B, A, C, D. So we use the combinations formula to solve this question.
Combinations formula:
[tex]C_{n,x}[/tex] is the number of different combinations of x objects from a set of n elements, given by the following formula.
[tex]C_{n,x} = \frac{n!}{x!(n-x)!}[/tex]
In how many ways can the positions be filled if 2 women and 2 men are hired?
2 women from a set of 6.
2 men from a set of 5.
So
[tex]T = C_{6,2} \times C_{5,2} = \frac{6!}{2!(6-2)!} \times \frac{5!}{2!(5-2)!} = 120[/tex]
The positions can be filled in 150 ways.
The number of ways the position can be filled with 2 women and 2 mean is 150
The number of people is:
[tex]\mathbf{Women = 6}[/tex]
[tex]\mathbf{Men = 5}[/tex]
The number of selection is:
[tex]\mathbf{Women = 2}[/tex]
[tex]\mathbf{Men = 2}[/tex]
So, the number of ways of selection is calculated using:
[tex]\mathbf{Ways = ^nC_r}[/tex]
This gives
[tex]\mathbf{Ways = ^6C_2 \times ^5C_2}[/tex]
Apply combination formula
[tex]\mathbf{Ways =15 \times 10}[/tex]
[tex]\mathbf{Ways =150}[/tex]
Hence, the number of ways the position can be filled with 2 women and 2 mean is 150
Read more about combination at:
https://brainly.com/question/8018593