Complete question:
Two sides of a right triangle measure 7 units and 3 units. What is the area of the square that shares a side with the third side of the triangle?
Answer:
[tex]C = (\sqrt{58}) ^2[/tex]
Step-by-step explanation:
Given:
A = 7 units
B = 3 units
To find the length of the third side, let's use Pythagoras theorem.
C² = A² + B²
Substituting figures, we have:
C² = 7² + 3²
C² = 49 + 9
C² = 58
[tex] C = \sqrt{58} [/tex]
The length of the third side, C is [tex] \sqrt{58} [/tex] units.
Since the length of the third side is [tex] \sqrt{58} [/tex] units, the area of the square that shares a side with the third side of the triangle would be C².
Therefore, C² = [tex] \sqrt{58}^2 [/tex]
