There were 5 bills of '1' and 9 bills of '5'.
Step-by-step explanation:
let the number of '1' bill be x
let the number of '5' bill be y.
Total number of bills = 14
x + y = 14 ..[1]
Worth of 14 bills = 50
So,x\times 1+y\times 5=\$50x×1+y×5=$50
x+5y=50x+5y=50 ..[2]
x + y = 14
x = 14 - y
Putting value of x in [2]:
14- y +5y=5014−y+5y=50
y=\frac{50-14}{4}=9y=
4
50−14
=9
y = 9
x = 14-y = 14 - 9 = 5
There were 5 bills of '1' and 9 bills of '5'.
