Answer:
(-0.198, 0.98).
Step-by-step explanation:
So, in this question we are given the following parameters or information or data that is going to assist us in determining the solution to this question. So, we have that;
" A triangle in the unit circle has a central angle that is 140°"
Hence, we are to determine the point that is in Quadrant II. So, let us dive right into the solution to the question below;
For a unit circle the value for the radius, r = 1. For the x, we have that;
x = r × cos φ and for y ---------------------(1).
x = 1 × cos 140° = cos 140° = - 0.198.
For y, we have that y = r × sin φ. -----(2).
y = 1 × sin 140° = sin 140° = 0.98.
Hence, the point that is in Quadrant II = (x,y) = (- 0.198, 0.98).
Please Note that your calculator is in radians(rad).
