Point Q is equidistant from AB and AC. What must be true about Q?
Chose from the following
A. It's on the perpendicular bisector of AB
B. It's on the perpendicular bisector of AC
C. BQ=CQ
D. It is on the angle bisector of ∠BAC.

Given that point Q is equidistant from AB and AC. This implies that AB and AC forms an angle BAC i.e <BAC. An equidistant point is a point that has the same distance from two different reference points.

Bisection is the process by which a line or angle is divided into two equal parts. A line that passes through the point of division is called a bisector, which is of equal distance to either of the reference points.

Thus by construction, a point that would be of equal distance to AB and AC is on an angle bisector of <BAC. So that point Q is on the angle bisector of <BAC.

Point Q is equidistant from AB and AC. What must be true about Q? Chose from the following A. It's on the perpendicular bisector of AB B. It's on the perpendicular bisector of AC C. BQ=CQ D. It is on the angle bisector of ∠BAC.

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Point Q is equidistant from AB and AC. What must be true about Q?
Chose from the following
A. It's on the perpendicular bisector of AB
B. It's on the perpendicular bisector of AC
C. BQ=CQ
D. It is on the angle bisector of ∠BAC.