Question

if 20.0 g H2SO4 is dissolved to make 250.0 mL of a solution, what is the molarity of this solution?

Answer 1

Answer:

0.816  M

Explanation:

Given data

• Mass of sulfuric acid (solute): 20.0 g

• Volume of solution: 250.0 mL

Step 1: Calculate the moles of solute

The molar mass of sulfuric acid is 98.08 g/mol.

$20.0 g \times \frac{1mol}{98.08 g} =0.204mol$

Step 2: Calculate the liters of solution

We will use the relationship 1 L = 1,000 mL.

$250.0mL \times \frac{1L}{1,000mL} =0.2500L$

Step 3: Calculate the molarity of the solution

$M = \frac{moles\ of\ solute }{liters\ of\ solution} = \frac{0.204mol}{0.2500L} =0.816 M$