Question

Suppose the number of dropped footballs for a wide receiver over the course of a season are normally distributed with a mean of 16 and a standard deviation of 2. What is the z score for a wide reciever who dropped 13 footballs over the course of a season ?

Answer 1

Answer:

The z score for a wide receiver who dropped 13 footballs over the course of a season

          Z = - 1.5

Step-by-step explanation:

Explanation:-

Given Population mean  ' μ'= 16

Standard deviation of Population 'σ' = 2

Let 'x' be the Random Variable of Normal distribution

Given x = 13 foot balls

The z score for a wide receiver who dropped 13 footballs over the course of a season

                $Z = \frac{x-mean}{S.D}$

               $Z = \frac{13 -16}{2} = \frac{-3}{2} = -1.5$

Final answer:-

The z score for a wide receiver who dropped 13 footballs over the course of a season

          Z = - 1.5

Answer 2

Answer:

-1.5

Step-by-step explanation: