Question

1) Find the concentration of a solution containing 300g of NaCl and 2L of water.
a) First find the molar mass of NaCl using a periodic table.
b) Convert 300g of NaCl into Mols of NaCl
c) Divide the Mols of solute by 2L, the liters of solution.​

Answer 1

Answer:

a) 58.44 g/mol

b) 5.133 moles of NaCl

c) 2.566 M

Explanation:

a) The molar mass of NaCl is

   Na: 22.99

   Cl: 35.45

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 NaCl= 58.44 g/mol

b) 300 grs of NaCl x (1 mol NaCl / 58.44 grs NaCl) = 5.133 moles of NaCl

c) M= n/L

   M = 5.133 moles NaCl/ 2L = 2.566 M NaCl