A motorboat moves across a lake at a constant speed. When it begins, it is 37

km from the shore. After 6 minutes, it is 19 km from the shore. Which

function describes the motorboat's distance from the shore?

O A. y=-6x+37

O B. y=-3x + 37

O C. y = 6x6 37

O D. y = 3x + 37

Respuesta :

Answer:

[tex] (x_1 = 0 , y_1 = 37)[/tex]

[tex] (x_2 = 6 , y_2 = 19)[/tex]

And finding the slope we got:

[tex] m = \frac{19-37}{6-0}= -3[/tex]

And then the function would be given by:

[tex] y = -3x +b[/tex]

And using the info from the first point we can find the y intercept

[tex] 37 = -3*0 +b[/tex]

b =37

And the model ould be given by:

[tex] y = -3x +37[/tex]

O B. y=-3x + 37

Step-by-step explanation:

For this case we assume that we can model the motorboard distance with a linear function given by:

[tex] y = mx+b[/tex]

Where m is the slope given by:

[tex] m =\frac{y_2 -y_1}{x_2 -x_1}[/tex]

Where y represent the distance and x the time in minutes. And we have the following info given:

[tex] (x_1 = 0 , y_1 = 37)[/tex]

[tex] (x_2 = 6 , y_2 = 19)[/tex]

And finding the slope we got:

[tex] m = \frac{19-37}{6-0}= -3[/tex]

And then the function would be given by:

[tex] y = -3x +b[/tex]

And using the info from the first point we can find the y intercept

[tex] 37 = -3*0 +b[/tex]

b =37

And the model ould be given by:

[tex] y = -3x +37[/tex]

O B. y=-3x + 37

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