Answer:
[tex] (x_1 = 0 , y_1 = 37)[/tex]
[tex] (x_2 = 6 , y_2 = 19)[/tex]
And finding the slope we got:
[tex] m = \frac{19-37}{6-0}= -3[/tex]
And then the function would be given by:
[tex] y = -3x +b[/tex]
And using the info from the first point we can find the y intercept
[tex] 37 = -3*0 +b[/tex]
b =37
And the model ould be given by:
[tex] y = -3x +37[/tex]
O B. y=-3x + 37
Step-by-step explanation:
For this case we assume that we can model the motorboard distance with a linear function given by:
[tex] y = mx+b[/tex]
Where m is the slope given by:
[tex] m =\frac{y_2 -y_1}{x_2 -x_1}[/tex]
Where y represent the distance and x the time in minutes. And we have the following info given:
[tex] (x_1 = 0 , y_1 = 37)[/tex]
[tex] (x_2 = 6 , y_2 = 19)[/tex]
And finding the slope we got:
[tex] m = \frac{19-37}{6-0}= -3[/tex]
And then the function would be given by:
[tex] y = -3x +b[/tex]
And using the info from the first point we can find the y intercept
[tex] 37 = -3*0 +b[/tex]
b =37
And the model ould be given by:
[tex] y = -3x +37[/tex]
O B. y=-3x + 37