Question

A person places $2150 in an investment account earning an annual rate of 3.3%, compounded continuously. Using the formula V = P e r t V=Pe rt , where V is the value of the account in t years, P is the principal initially invested, e is the base of a natural logarithm, and r is the rate of interest, determine the amount of money, to the nearest cent, in the account after 2 years.

Answer 1

We have been given that a person places $2150 in an investment account earning an annual rate of 3.3%, compounded continuously. We are asked to find the amount of money is the account after t years.

We will use continuous compound interest formula to solve our given problem.

$A=P\cdot e^{rt}$

A = Final amount after t years,

P = Principal amount,

r = Annual interest rate in decimal form,

t = Time.

$r=3.3\%=\frac{3.3}{100}=0.033$

$P=2150$ and $t=2$.

$A=2150\cdot e^{0.33\cdot 2}$

$A=2150\cdot e^{0.66}$

$A=2150\cdot 1.9347923344020315$

$A=4159.803518964$

Upon rounding to nearest cent, we will get:

$A\approx4159.80$

Therefore, there will be approximately $4159.80 in the account after 2 years.

Answer 2

Answer: 2296.69

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