Answer:
I = 12*B (the information about B does not appear in the statement)
Explanation:
The motion of the segment of the circuit, in a constant magnetic field makes that opposite charges inside the segment separate of each other. This generate a induced potential difference at the ends of the segment that is given by the following formula:
[tex]\epsilon=vBL[/tex] (1)
v: speed of the segment = 2.0m/s
B: magnitude of the magnetic field
[tex]\epsilon=(2.0)(30.0)B=60.0B[/tex] (2)
The induced current calculated by replacing the result of (2) in the following formula:
[tex]I=\frac{\epsilon_o}{R}=\frac{60.0B}{5.0}=12B[/tex] (3)
Then, you only have to replace the value of the magnitude of the magnetic field B in (3) to calculate the current.
