What must be a factor of the polynomial function f(x) graphed on the coordinate plane below?

On a coordinate plane, a parabola opens up. It goes through (0, 3), has a vertex at (3.5, 3), and goes through (6, 0).
x – 3
x – 1
x + 1
x + 3

What must be a factor of the polynomial function fx graphed on the coordinate plane below On a coordinate plane a parabola opens up It goes through 0 3 has a ve class=

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Answer:

B) X-1

Step-by-step explanation:

just did the test and got it right

The factor of the polynomial function f(x) graphed on the coordinate plane below is x - 1

Before we can determine the factor of the polynomial, we need to first determine the zeros of the polynomial graph.

The point where the curve cuts the x-axis is the zeros of the polynomial graph.

For the given graph, we can see that the curve cuts the x-axis at x = 1 and x = 6

Hence the corresponding factors will be x - 1 and x - 6

Therefore, a factor of the polynomial function f(x) graphed on the coordinate plane below is x - 1

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