Question

a quarterback throws a football at 40.0 km/hr to a receiver 50.0 yd away. how much time does it take the ball to reach the receiver?

Answer 1

t=d/s
40km/h x 1093.61yd/1km x 1h/60min x 1min/60s

40 x 1093.61 = 43744.4yd
 60 x 60 = 3600sec

43744.4/3600= 12.15

distance/speed=time : 50yd/12.15yd/sec = 4.11sec

answer: 4.11sec

Answer 2

Explanation:

Given that,

The speed of a football, v = 40 km/h

The distance between a quarterback and a receiver is, d = 50 yards

To find,

The time taken by the ball to reach the receiver.

Solution,

First km/h is converted to m/s.

$40\ km/h=\dfrac{40\times 1000}{3600}\\\\=11.11\ m/s$

Also, $1\ yd=0.9144\ m\\\\50\ yd=45.72\ m$

Let t is the time taken by the ball to reach the receiver. We know that,

$\text{Speed}=\dfrac{\text{distance}}{\text{time}}$

So,

$t=\dfrac{d}{v}$

Put all the values,

$t=\dfrac{45.72}{11.11}\\\\t=4.115\ s$

or

$t=4.12\ s$

Answer:

The time taken by the ball to reach the receiver is $4.12\ s$.

Reference,

https://brainly.com/question/10812167