Question

How many electrons must be removed from a neutral, isolated conducting sphere to give it a positive charge of 8.0 x 10 8 C? [Q=ne]

Answer 1

Answer: the ball will have a charge of 8x10^8C when we remove 5x10^27 electrons.

Explanation:

If the sphere is neutral, then the charge of the sphere is 0C

Now, when we remove an electron (-1.6*10^-19 C) we are subtracting a negative number, so the new charge of the sphere is: 1.6*10^-19 C

Now, for N removed electrons, the charge of the sphere is:

N*1.6*10^-19 C

We want to find the number N when:

N*1.6*10^-19 C = 8.0x 10^8 C

N = (8.0/1.6)x10^(8 + 19) = 5x10^27 electrons.

Answer 2

Hence the number of electrons that must be removed from the given sphere is,

$X=5*10^{27}C$

Given-

In the problem there is a sphere with a neutral charge.

This means the charge on the sphere = 0C

We know that negative charge on an electron is,

$1.602*10^{-19}C$

to make this neutral charge sphere to the positive charge of

$8.0*10^{8}C$

we need to divide this positive charge with the charge of one electron

Now the number of electrons X with a negative charge will be equal to,

$X*1.602*10^{-19} = 8.0*10^{8}$

$X=\dfrac{8.0*10^{8}}{1.602*10^{-19}}$

$X=\dfrac{8.0*10^{8+19}}{1.602}}$

$X=5*10^{27}C$

Hence, the number of electrons that must be removed from the given sphere is,

$X=5*10^{27}C$

For more about the charge of electrons follow the link,

https://brainly.com/question/75389