Answer:
∠ p ≈ 59°
Step-by-step explanation:
Using Pythagoras' identity in right triangle ABD to find DB
DB² = 5² + 6² = 25 + 36 = 61 ( take square root of both sides )
DB = [tex]\sqrt{61}[/tex]
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Using the cosine ratio in right triangle DBC
cos p = [tex]\frac{adjacent}{hypotenuse}[/tex] = [tex]\frac{DC}{DB}[/tex] = [tex]\frac{4}{\sqrt{61} }[/tex] , thus
p = [tex]cos^{-1}[/tex] ( [tex]\frac{4}{\sqrt{61} }[/tex] ) ≈ 59°
Answer:
59
Step-by-step explanation: I got it right so u should too :)
