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caylus
Hello,
f(x)=y=4x+12

x=4y+12
==>4y=x-12
==>y=x/12- 3

g(x)=x/12 -3


Answer:

[tex]f^{-1}(x)=g(x)=\frac{x-12}{4}[/tex]

Step-by-step explanation:

The problem tell us that [tex]g(x)[/tex] is the inverse of [tex]f(x)[/tex], where:

[tex]f(x)=4x+12[/tex]

So, we need to find the inverse function of [tex]f(x)[/tex] in order to find [tex]g(x)[/tex]

Let's find the inverse function using the following steps:

1. Replace  [tex]f(x)[/tex] with [tex]y[/tex]:

[tex]f(x)=y=4x+12[/tex]

2. Solve the equation for [tex]x[/tex]:

[tex]\frac{y-12}{4} =x[/tex]

3. Replace every [tex]x[/tex] with a [tex]y[/tex] and replace every [tex]y[/tex] with a [tex]x[/tex]:

[tex]y=\frac{x-12}{4}[/tex]

4. Finally, replace [tex]y[/tex] with [tex]f^{-1}(x)[/tex]

[tex]f^{-1}(x)=\frac{x-12}{4}[/tex]

Therefore:

[tex]g(x)=f^{-1}(x)=\frac{x-12}{4}[/tex]

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