Answer:
The correct answer is option 1. [tex]\frac{2}{3} \pi x^3[/tex] cubic units.
Step-by-step explanation:
The formula for the volume, V of a right angled cone is given as:
[tex]V = \dfrac{1}{3} \pi r^{2} h ...... (1)[/tex]
Where, [tex]\pi = 3.14[/tex]
[tex]r[/tex] is the radius of the circular base of the cone.
[tex]h[/tex] is the height of the cone.
We are given that height is twice of the radius of its base.
Let the radius of base = [tex]x[/tex] units
Now, As per the question statement,
The height of cone= [tex]2 \times x[/tex] units
Putting the values of [tex]r, h[/tex] in equation (1) to find the volume:
[tex]\Rightarrow \dfrac{1}{3} \times \pi \times x^{2} \times 2x\\\Rightarrow \dfrac{2}{3}\pi x^{3}[/tex]
Hence, the correct answer is option 1. [tex]\dfrac{2}{3}\pi x^{3}[/tex] cubic units.